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8v^2+67v+24=0
a = 8; b = 67; c = +24;
Δ = b2-4ac
Δ = 672-4·8·24
Δ = 3721
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3721}=61$$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(67)-61}{2*8}=\frac{-128}{16} =-8 $$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(67)+61}{2*8}=\frac{-6}{16} =-3/8 $
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